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This temple has its gong in the shape of a solid sphere..however the hinge (as shown) is really weak..

Specify: Where should the gong be hit by devotees to impart minimum damage to the weak hinge????..in terms of the radius of the gong.

And yaar i'm really busy these days..so i'll post all the solutions some other day..

Aur yaar this one's important and good..
I would like you to solve the same for a rigid body of radius 'R' and radius of gyration 'K'...
For a rod??? you could mail your ans. to Tendulkar..he would love to save his hands from those jerks....

13 comments:

  1. Sambhav GuptaMarch 9, 2010 at 9:48 PM

    This comment has been removed by a blog administrator.

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  2. AnujMarch 9, 2010 at 9:57 PM

    damn..that was quick..could you do the same for a general rigid body??

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  3. Sambhav GuptaMarch 9, 2010 at 10:20 PM

    yup...i had done that....just have to replace the value of the moment of inertia....

    but i wouldn't be posting it here for obvious reasons...

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  4. Sambhav GuptaMarch 10, 2010 at 12:16 AM

    but i think we should be given the distance of the COM from the hinge....i mean....if the 'general body' is not a regular body, then we do not know the position of COM, but we still are given the MOI

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  5. vjiay kharyaMarch 10, 2010 at 11:14 AM

    is it at the same horizontal plane as the centre of mass? i simply used the parallel axis theorem

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  6. AnujMarch 10, 2010 at 1:12 PM

    yes Sambhav..you are right..but for a general rigid body, you can assume all the variables you like!

    no vijay..the hoz. plane is passes thru the pt. where the body has been struck

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  7. UnknownMarch 10, 2010 at 5:09 PM

    i dont able to solve it please reply me complete solution please

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  8. AmitMarch 10, 2010 at 6:03 PM

    its coming to be (2/5)*R
    for a general ody its k^2/(distance of hinge from centre of mass)

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  9. AnujMarch 10, 2010 at 6:14 PM

    haan yaar..but you calculated the distance from the center..others from the hinge..

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  10. UnknownMarch 10, 2010 at 6:33 PM

    PLEASE PROVIDE YOUR SOLUTION. PLEASE I AM WAITING

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  11. AmitMarch 10, 2010 at 7:00 PM

    you might have done the billiard question in the module.
    same approach
    just replace Vcm=wr
    Impulse about hinge is to be minimum therefore it is taken zero and it is possible too. that's why answer is coming.

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  12. UnknownMarch 10, 2010 at 8:08 PM

    Anuj sir please give the solution completely

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  13. ankush sachdevaMarch 10, 2010 at 10:04 PM

    ohh yes amit u r rite,i had missed linear impulse eqn

    and amrit....

    let I be impulse from the gong at x distance below hinge
    angular impulse equation
    Ix=7/5 MR^2 w

    assuming impulse from hinge zero

    linear impulse equation
    I=M Vcm

    Vcm = wR

    solve them get the answer

    ReplyDelete

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