Whenever two bodies are in contact, their relative accn is parallel to the palne of contact.
Calculate the accn. of the plank of mass 'm' in the 1st diagram. Angle of the wedge is A.
In the second diagram, find the accn of the rod kept on top of the rings. Assume the rings roll without slipping.
Description:
i have shown the front and top views of the system; consisting of a short and thin rod kept on top of two rings whose planes are parallel to each other, but the centers are displaced.
The rod moves vertically down and there is always symmetry wrt. the two rings. Find the accn of the rod when the angle that the dotted lines make with the hoz. are 'A' each.
acceleration of rod is
ReplyDeletemg/2M
for the wedge problem
ReplyDeleteaccl= mg/(m+2M(cot^2A))
im getting exactly the same as what ankush got
ReplyDeletefor the wedge one I am getting
ReplyDeletea of rod= mg/(m+2M(cot^2A))
And for the ring one
a of ring = (mg(cosA)^2)/(m(cosA)^2+M)