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What is the velocity of the ball when it reaches th bottom of the bowl?

Assume its collision with the bowl to be completely inelastic. The accn. due to gravity is g.

14 comments:

  1. akash rupelaMarch 11, 2010 at 12:04 AM

    is it root[gR ( 2- root3/2) ]

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  2. anuragMarch 11, 2010 at 12:05 AM

    is it root[gR(8-3root3)/4]

    ReplyDelete
  3. Sambhav GuptaMarch 11, 2010 at 12:10 AM

    [8-3[3]Rg]/2

    []=sqrt..

    ?

    ReplyDelete
  4. akash rupelaMarch 11, 2010 at 12:17 AM

    Yes I am also getting same ans after correcting my calculation mistake as Sambhav and Anurag

    ReplyDelete
  5. AnantMarch 11, 2010 at 12:18 AM

    This comment has been removed by the author.

    ReplyDelete
  6. AnantMarch 11, 2010 at 12:19 AM

    v^2 = gR(8-3root3)/4 ??

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  7. rohanMarch 11, 2010 at 12:38 AM

    WHERE IS CONDITION OF ZERO IMPULSE AT THE HINGE APPLICATION. PLEASE EXPLAIN SIR?!!!!!!!!! IN YOUR SOLUTION OF GONG?!!!!PLEASE

    ReplyDelete
  8. ankush sachdevaMarch 11, 2010 at 12:39 AM

    i m also getting same as sambhav and anurag

    ReplyDelete
  9. Anmol JainMarch 11, 2010 at 12:45 PM

    m also getting same as sambhav...wats the correct answer??

    ReplyDelete
  10. Sambhav GuptaMarch 11, 2010 at 12:56 PM

    perhaps yahi hoga....sabka to yahi aa rha hai...
    question bhi asaan sa he hai(as compared to others)

    or maybe not...
    ?

    ReplyDelete
  11. Anmol JainMarch 11, 2010 at 1:08 PM

    yaar kabhi kabhi aasan dikhne wale question bhi top type nikal jaate hain..its said na never underestimate ur enemy....
    bt i feel r answer is rite....bas m waitng fr anuj bhaiya to approve.

    ReplyDelete
  12. rohanMarch 11, 2010 at 1:52 PM

    ANKUSH,ANMOL,SAMBHAV ANYBODY PLEASE REPLY WHY THER IA N<N* IN BRICK PROBLEM AS THERE IS FRICTION IN BOTH PARTS OF BRICK

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  13. AnujMarch 11, 2010 at 5:22 PM

    all of you got it right.. the ball,s velocity just before hitting the bowl is trivial..on the inelastic collision, the ball loses all velocity perpendicular to the surface.

    whats left is the tangential component! cons. of eng. gives the velocity at the bottom..

    ReplyDelete
  14. AnantMarch 12, 2010 at 3:03 AM

    @Rohan
    friction in both parts is in the same direction and providing same and not opposite torque. its giving clockwise torque to the centre which needs to be balanced so normal reaction is different.

    ReplyDelete

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