Here's the Soln:
x=9LCosQ...
So dx/dt=-9LSinQ(dQ/dt)
to evaluate dQ/dt use:
y=LSinQ
dy/dt=v=LCosQ(dQ/dt)
So dx/dt=9LSinQ(v/LCosQ)...so, dx/dt=9v...
Dudes, this is the Standard approach:
1)You write the coordinates of the point in question and those of the pts. whose velocities are given...relative to a fixed pt (the origin).
2)Differentiate these..
bhaiya is velocity of snake head changing wid time?
ReplyDeletebecause i assumed it to be constant and used average velocity concept , i m getting wrong answer
time is L/v*root2
horizontal distance moved by snake head is 9(L-L/root2)
ya..snake's velocity is surely changing with time..
ReplyDelete