Supplement:

Just for fun:
A particle is projected with a velocity V at an angle Q with the horizontal..
After what time will its velocity become perpendicular to its initial velocity??

8 comments:

  1. it is a module subjective question bhaiya...
    (u*cosec Q)/g

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  2. that's why i asked it.

    the module solution was quite long in my time..maybe they changed it. if not, then it would take some real typing effort!

    Anyways it was for fun..but i have a good solution for this one!

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  3. shorter method...resolve g along direction of velocity

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  4. mr gta got it right! man! you people are smart!

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  5. hows that...?
    in the module they have simply applied first equation of motion along the two directions and then substituted..

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  6. you do not always have to take the axes to be horizontal and vertical..here there is a more obvious choice of axes.

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  7. nice shortcut,..i'll remember it,.......can be useful in other questions as well

    thnx..

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  8. you may call it a shortcut..but i'll say that it is the more natural way..

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