The Origins2:
There comes a time during JEE prepn. when one is all crazy abt integration..and moment of inertia..center of mass etc. One feels powerful with this ability! I got this question at that time.
But one may get stumped when the integration has to be replaced by a summation..as in problem no. 2..
The question i originally solved was to find out the moment of inertia of the rod abt an axis perpendicular to it and passing thru its COM.
Not easy??? anyone wanna give a shot?
So guys.. Saturday-Sunday you get your cute problems. Other days..when i got some less fun tasks and lesser time at hand..you get some good problems for practice..related to these big ones...
Then it must be that 3 problems on sat n sun each. Accepted ?
ReplyDeleter u asking to find the MOI about the COM in problem 2?
ReplyDelete[(100)(101)/2]^2 - [(100)(101)/2](67)(67)
2833050 units?
Yo .. m also gettin the same!!
ReplyDeleteI did it wid a looooond method .. crap !
Sambhav, you've done it right..
ReplyDeleteProbably applied the perpendicular axis theorem??
NO ..
ReplyDeleteParalel axis theorm !!
perhaps he meant the same..
ReplyDeletebhavnao ko samjho..
yes i applied the parallel axis axis theorem bhaiya...
well..... i didnt think of parallel axis theorem.But it was still not lengthy.
ReplyDeleteSum(r^2(67+r)) from r=1 to 33
+
Sum(r^2(67-r)) from r=1 to 66