Some of you had your TS today. Bet you got loads of interesting Physics problems. Anyone wanna discuss some? If yes, post them as comments to this post.
I'll be happy to have good new problems in my stock!
Here's a simple tricky question. Ive got two wedges, fixed to the ground, from each hinged a pulley. two blocks(one on each wedge) are attached to the pulleys with an ideal thread. The block on the left wedge is attached to the pulley on the right wedge with another ideal thread. angle of inclination of the wedges from the horizontal are 60(wedge on the left) and 30(wedge on the right). give me the acceleration of the left block.
@kapil ts was primarily for 12p bt 12 stdnts were also allwed/dnt wrry abt the questns-people will put up the good ones on the testpaper discussion forum on vm site @vibhav cudnt understand the figure..
it doesnt does it? there is no length constraint. at any given point of time the block on the left wedge has more acceleration/velocity than the block on the right wedge. the string connecting the two blocks will posess no tension. try calculating it, it'll be in negative. i remember everyone except one person in our batch getting this question wrong.
that means we have another point to remember.. if someone asks you the acceleration...and you have applied length constraint..and then calculated for 'a'..then you also have to calculate 'T' to validate the constraint..
somewat. its not something i do though. calculating tension might waste some time. u just need an eye for these questions. i mean, imagine if u didn know zilch about length constraints.... you would have got the anwer right then, wouldnt u?
which batch had the TS?
ReplyDeleteXIIth pass? or 2011?
Really have no idea.. Digvijay said he had one today..probably he's in 12th...
ReplyDeleteit was for both 12th n 12P..
ReplyDeleteHere's a simple tricky question.
ReplyDeleteIve got two wedges, fixed to the ground, from each hinged a pulley. two blocks(one on each wedge) are attached to the pulleys with an ideal thread. The block on the left wedge is attached to the pulley on the right wedge with another ideal thread.
angle of inclination of the wedges from the horizontal are 60(wedge on the left) and 30(wedge on the right).
give me the acceleration of the left block.
Options are
ReplyDelete1>g
2>g/2
3>[g(sqrt3)/2)]
4> (g/4)[1+sqrt(3)]
vaibhav could u just post the figure fr the Q
ReplyDeleteDigvijay, the TS can't be 4 12th as we had our TS last Sunday
ReplyDeletemaybe 4 12th pass and please post some interesting questions from the TS
if the masses are same...(which obviously shoud be since nothing specified)....ans is 4....(g/4)[1+sqrt(3)]
ReplyDeleteanyone else gave it a try?
ReplyDeletebhaiya plz post ques in mathematic and chem as well
ReplyDeletekindly tell the answer vibhav..
ReplyDelete@kapil ts was primarily for 12p bt 12 stdnts were also allwed/dnt wrry abt the questns-people will put up the good ones on the testpaper discussion forum on vm site
ReplyDelete@vibhav cudnt understand the figure..
k. ill get a better figure. sambhav, u got the tricky part right but still u got it wrong!
ReplyDeleteanswer is 3
hmm...that would be if the second string also has no tension...
ReplyDeletehow's that done...?
it doesnt does it?
ReplyDeletethere is no length constraint.
at any given point of time the block on the left wedge has more acceleration/velocity than the block on the right wedge.
the string connecting the two blocks will posess no tension.
try calculating it, it'll be in negative.
i remember everyone except one person in our batch getting this question wrong.
that means we have another point to remember..
ReplyDeleteif someone asks you the acceleration...and you have applied length constraint..and then calculated for 'a'..then you also have to calculate 'T' to validate the constraint..
Am i right?
somewat. its not something i do though. calculating tension might waste some time. u just need an eye for these questions.
ReplyDeletei mean, imagine if u didn know zilch about length constraints.... you would have got the anwer right then, wouldnt u?