
The dual-wedge shown in the figure is MASSLESS. All surfaces are smooth.
Find the min ratio m1/m2 so that the ball m2 'starts climbing up the wedge'..ie. it starts moving up the incline in the direction shown.
Problem Statement Courtesy: Ashish Gaurav, the second-best physics guy I've ever seen.
@administrators, can a blog archive be added so, that we can search previous posts if needed.
ReplyDeleteIt is really a pain to search your past.
is it sec a
ReplyDeletethanx a lot for the archive :)
ReplyDeletem1/m2 > sec^2(A)??
ReplyDeletei'm too getting sec^2{a}
ReplyDeletebhaiya...pls tell the right ans...or some hint(if we r wrong)
answer's sec(A).
ReplyDeleteGOT IT !!!!!! DAMN GOOD :D
ReplyDeleteplease help, i did this:
ReplyDeletesince m2 is about to move on Wedge 2(ie left wedge)
so normal due to right wedge on m2=0
since M=0, so N( by W2 on m2)= N(by W1 on m1)= N
now , eqn.s of dynamics.on m2, m1...
( i'll write them if anyone requires)...
give m1/m2= sec^2 A
it could be sec^2. its been a very long time.
ReplyDeletei think u should post your equations, i can't do anything else
shivam could check them, or maybe i will.
me too getting sec^2(A)
ReplyDeletedid almost the same way as shaan..
ReplyDeleteequated net force on the massless wedge to zero..
This comment has been removed by the author.
ReplyDeletethere's no collision pulkit.. :)
ReplyDeleteGot it now.Vaise,there was another error also.:)
ReplyDeletepulkit,
ReplyDeleteplease confirm the other ERROR was
"when m2 starts acc'ing, M1 WILL BE IN THE MIDDLE OF THE 2 WEDGES"
Bhaiya plz provide us with the solution.. most of us(including me) are confused over this..
ReplyDeleteit is an old question, discussed on the blog. you can see that, bhaiya had written some hints there
ReplyDelete