William Pickering:


The dual-wedge shown in the figure is MASSLESS. All surfaces are smooth.
Find the min ratio m1/m2 so that the ball m2 'starts climbing up the wedge'..ie. it starts moving up the incline in the direction shown.

Problem Statement Courtesy: Ashish Gaurav, the second-best physics guy I've ever seen.

17 comments:

  1. @administrators, can a blog archive be added so, that we can search previous posts if needed.
    It is really a pain to search your past.

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  2. thanx a lot for the archive :)

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  3. i'm too getting sec^2{a}

    bhaiya...pls tell the right ans...or some hint(if we r wrong)

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  4. please help, i did this:

    since m2 is about to move on Wedge 2(ie left wedge)
    so normal due to right wedge on m2=0

    since M=0, so N( by W2 on m2)= N(by W1 on m1)= N

    now , eqn.s of dynamics.on m2, m1...
    ( i'll write them if anyone requires)...
    give m1/m2= sec^2 A

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  5. it could be sec^2. its been a very long time.

    i think u should post your equations, i can't do anything else

    shivam could check them, or maybe i will.

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  6. did almost the same way as shaan..
    equated net force on the massless wedge to zero..

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  7. This comment has been removed by the author.

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  8. there's no collision pulkit.. :)

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  9. Got it now.Vaise,there was another error also.:)

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  10. pulkit,
    please confirm the other ERROR was
    "when m2 starts acc'ing, M1 WILL BE IN THE MIDDLE OF THE 2 WEDGES"

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  11. Bhaiya plz provide us with the solution.. most of us(including me) are confused over this..

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  12. it is an old question, discussed on the blog. you can see that, bhaiya had written some hints there

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