
Recently, Sambhav made a post about a nice method to solve SHM questions. I remember getting frustrated over such problems: the solution always seemed a bit too lengthy.
Here's your chance to get a firm grasp over the method. Try finding out the period of oscillation.
I request Sambhav to post the solution after 2 days or so.
(I hope that this one can be solved using the method).
-Anuj
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ReplyDeletekeq = 96/107k
ReplyDeletei guess its keq = 96k/107..
ReplyDeletebut couldn't infer how to do it with that method though..
even i got 96k/107m, i found a lil 'intricacy' in that method, will discuss soon
ReplyDeleteMe too getting the same i.e., Keq = 96k/107
ReplyDeletei got 96k/107 .....using "The Bhaskar bhaiyya method" ....for such problems....(i dont know if
ReplyDeletethats the one u guys used )..i find it the quickest
getting the same,
ReplyDeletei used x= x1+x2/2+ x3/4
and T= kx1= 2[3kx2]= 4[2kx3]
so Keq = 96k/107..
how to use that series method??
@chetas: it'll be very kind of u if u can giv a hint to "bhaskar bhaiya's method"...
thanks
on the series method,
ReplyDeletenot applicable here 'directly'
we can use seies method only when F=k1x1=k2x2=k3x3=k4x4=k(net)x(net)...., and x1+x2+x3+x4=x(net)
here, the second relation is not a direct one, instead, we have to use constraints to get the relation x(net)=x1+x2/2+x4/4
and if i am using constraints anyway, what good is the series method?
@sambhav bhaiya
ReplyDeletewhere can i find such problems?