Practice:


Recently, Sambhav made a post about a nice method to solve SHM questions. I remember getting frustrated over such problems: the solution always seemed a bit too lengthy.

Here's your chance to get a firm grasp over the method. Try finding out the period of oscillation.
I request Sambhav to post the solution after 2 days or so.

(I hope that this one can be solved using the method).
-Anuj

10 comments:

  1. This comment has been removed by the author.

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  3. i guess its keq = 96k/107..

    but couldn't infer how to do it with that method though..

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  4. even i got 96k/107m, i found a lil 'intricacy' in that method, will discuss soon

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  5. Me too getting the same i.e., Keq = 96k/107

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  6. i got 96k/107 .....using "The Bhaskar bhaiyya method" ....for such problems....(i dont know if
    thats the one u guys used )..i find it the quickest

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  7. getting the same,

    i used x= x1+x2/2+ x3/4
    and T= kx1= 2[3kx2]= 4[2kx3]
    so Keq = 96k/107..

    how to use that series method??

    @chetas: it'll be very kind of u if u can giv a hint to "bhaskar bhaiya's method"...

    thanks

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  8. on the series method,
    not applicable here 'directly'
    we can use seies method only when F=k1x1=k2x2=k3x3=k4x4=k(net)x(net)...., and x1+x2+x3+x4=x(net)

    here, the second relation is not a direct one, instead, we have to use constraints to get the relation x(net)=x1+x2/2+x4/4

    and if i am using constraints anyway, what good is the series method?

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  9. @sambhav bhaiya
    where can i find such problems?

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