c'mon...its not that difficult..
is this from semiconductors? :P
no...though i'm quite good at semiconductors :P.this is an 'analog' device, and 'analog' has got little to do with semiconductors..actually, the connection between 'A' and 'B' is realized using semiconductors. but that is of little significance.
let me define some terms specifically in this context:1) A short circuit means that the 2 points are at the same potential. Forget your previous notions for a minute. 2) An open circuit means that no current can flow between the 2 points.
explaining amplification and amplification factor wud have been of use :P
if Vo=k(Vi) where k is a constant,we say that Vo is an amplified version of Vi, and the amplification factor is 'k'.
here's the steps:1)Apply KCL at the junction pointed by the blue arrow.1a)What is the potential of the junction?1b)Why does the small wire shown in blue carry 0 current?
the potential of d junction is zero because of the short circuit..but why will d current be zero.?
c'mon...its not that difficult..
ReplyDeleteis this from semiconductors? :P
ReplyDeleteno...though i'm quite good at semiconductors :P.
ReplyDeletethis is an 'analog' device, and 'analog' has got little to do with semiconductors..
actually, the connection between 'A' and 'B' is realized using semiconductors. but that is of little significance.
let me define some terms specifically in this context:
ReplyDelete1) A short circuit means that the 2 points are at the same potential.
Forget your previous notions for a minute.
2) An open circuit means that no current can flow between the 2 points.
explaining amplification and amplification factor wud have been of use :P
ReplyDeleteif Vo=k(Vi) where k is a constant,
ReplyDeletewe say that Vo is an amplified version of Vi, and the amplification factor is 'k'.
here's the steps:
ReplyDelete1)Apply KCL at the junction pointed by the blue arrow.
1a)What is the potential of the junction?
1b)Why does the small wire shown in blue carry 0 current?
the potential of d junction is zero because of the short circuit..
ReplyDeletebut why will d current be zero.?