1) How many ordered pairs (a,b) of natural numbers have 17640 as their LCM?
2) The set of natural numbers {a1,a2,a3,...,an} is called a partition of 'N' if a1+a2+a3+...+an=N.
Consider all the partitions of N=176. There is a partition with the maximum product among all the partitions.
What's this maximum product?
P.S: don't Google these questions.
276 and (44)^4
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ReplyDeleteedit:it shud be 4^44 for 2nd ques
ReplyDeleteI think For second question
ReplyDelete(2)^88
1.I got 85, though I think definitely I have dn some mistake. method is x1+x2+x+x4+x5=8 now do by particular permutation and combination method. By finding range of these factors=2,3,5,7 x5 is extra which would make sum as 8.
ReplyDelete2.yes 2^88 or 4^44-one and the same thing
no and no.
ReplyDeletem getting 263 "unordered pairs" of natural numbers for d first one for sure..
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ReplyDeletethe second one should be 2*3^58 i guess..
ReplyDelete1.12
ReplyDeletebhaiya please tell, if my approach to first question was incorrect. Because that's how we found no.s which can be formed from the given no.
ReplyDeleteAlso I forgot to take ordered pair, so it should be 85C2
I got the answer of the Answer of the second problem.I think so.I am getting 2 * 3^58.
ReplyDeletePlease bhaiya tell am i right??
to second question also, now I am getting somewhat feel.
ReplyDeleteApply AM >= GM
product >= (176)^n
now I couldn't solve so, googled it :p, got it now. :)really good question
to first question, I have attempted it myself(that is why it is wrong)
@♥◘○µ╦┬░Γ╪╬└↑φΦ╫╛◙«½╣↔⌐☺♠♦♣◘○ ,
ReplyDeleteno, its incorrect
No i am correct.
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ReplyDeleteit should be 505 for 1st one right?
ReplyDeletefirst one is 525 ordered pairs akash.. : confirmed
ReplyDeleteand for 2nd one i agree with 2*3^58
ReplyDeleteyeah i m sorry, mismultiplied 21 and 25 :P
ReplyDeletefor second one as I found on internet is e^(176/e)
ReplyDeleteMr. Anonymous:
ReplyDeletethink urself.. is e a natural number??
or is 176/e a natural number??
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ReplyDeletehey.. can anyone find the number of partitions of a natural number n???
ReplyDeletem trying bt cudn't get it by now.. :-/
Yes i am very happy because i won question 2 competition.I stood first♣♣♠
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ReplyDeleteok..
ReplyDeletethnx akash.. u're right..
i found this creapy thing by the way lately..
http://en.wikipedia.org/wiki/Partition_(number_theory)#Partition_function
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ReplyDeleteI got to do some censorship..
ReplyDeletesorry bhaiya..
ReplyDeleteAs for the number of partitions of a natural number 'n', this was a question in our CSL105 major. I can't remember the soln. now.
ReplyDeleteMaybe someday, we'll have a piece of that too!
that would be fun
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ReplyDeletelets talk 'academic' stuff here...we have ole' facebook for our er...personal matters..
ReplyDeletehow do we get answer of first one?????????
ReplyDeleteis answer of 1st 525???
ReplyDeleteblah blah
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