All the wires shown in the figure (red color) have resistance 'R'. The only places where the wires are connected are the vertices of the large hexagon.
Find the resistance between points 1)'A' and 'B'. 2)'A' and 'C'.
Cool down xxx...If i didn't answer, it meant that I was busy or careless (you'd be too if you had 2 assignments, 2 quizzes, 1 interview and 1 re-minor scheduled in a week).
I particularly hated the last comment, you sort of crossed a line there..seriously!
The answer is probably R/3. Shourya had even posted the solution.
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ReplyDeletehey sambhav
ReplyDeletein this i am not able to apply perpendicular symmetry, aur along the line wali symmetry ismein lage gi nahin
how you did this
Hi Sambhav : plz. don't post the solution..yet.
ReplyDeleteR/3 ??
ReplyDeletesame as guntash
ReplyDeleteTotal resistance from A → B = 1 + 1.36 = 2.36 * R
ReplyDeleteR/3..
ReplyDeleter/3. all 4 black spots are at equal potentials. so there are total 5 resistances in parallel, 4 with res 2r and one with res r.
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ReplyDeleteThis comment has been removed by a blog administrator.
ReplyDeleteThis comment has been removed by a blog administrator.
ReplyDeleteThis comment has been removed by a blog administrator.
ReplyDeleteCool down xxx...If i didn't answer, it meant that I was busy or careless (you'd be too if you had 2 assignments, 2 quizzes, 1 interview and 1 re-minor scheduled in a week).
ReplyDeleteI particularly hated the last comment, you sort of crossed a line there..seriously!
The answer is probably R/3. Shourya had even posted the solution.
Now scroll back for a question titled "The Kings of S". And then think if there was a need for an answer.
ReplyDeleteSORRY BHAIYA FOR THE LAST COMMENT
ReplyDeleteBHAIYA WHAT IS THE ANSWER OF THE PROBLEM IN THE LINK http://anujkalia.blogspot.com/2010/09/friction.html#comments
ReplyDeletei dunno...forget it for now..probably the one which was posted by i guess three ppl. is right.
ReplyDelete