Because I can't think of anything better:

A hollow cylinder (radius=.5m) rolls without slipping down an incline. The length of the incline is 1m and the friction force acting on the cylinder is 200N.

Find the rotational work done by the friction force on the cylinder during its motion on the plane.

7 comments:

  1. somay jainSeptember 12, 2010 at 11:36 PM

    This comment has been removed by the author.

    ReplyDelete
  2. somay jainSeptember 12, 2010 at 11:56 PM

    dint see it was rotational work..
    200 maybe

    ReplyDelete
  3. shouryaSeptember 14, 2010 at 9:37 PM

    200 j.

    ReplyDelete
  4. Chiraag KapilSeptember 18, 2010 at 12:20 AM

    bhaiya is it 200 joules

    ReplyDelete
  5. rishabhSeptember 21, 2010 at 3:36 PM

    mine is -200 joules
    abhi rotational mechanics kiya nahi hai(2012 batch)
    but nothing seem some rotational concept
    i better leave this question

    ReplyDelete
  6. AnujSeptember 21, 2010 at 3:44 PM

    infact there is a lot of rotational concept involved here...

    Try to prove that for a any rigid body rolling without slipping, translational work by friction = -rotational work by friction.

    ReplyDelete
  7. Sambhav GuptaSeptember 21, 2010 at 6:23 PM

    rotational work=torque(.)theta

    torque is r(x)f, and theta measured anticlockwise, which is equivalent to measuring theta in the +Z direction

    translational work=force(.)displacement

    and, lastly, R(theta)=s

    assuming directions, we can now prove the required

    ReplyDelete

Subscribe to: Post Comments (Atom)