Friction:


What is the maximum weight of the block B which can be supported in the manner shown? (The pulley is smooth).


Note that the rod is nailed to the disc in the "black" region. The rod is also massless.

The coeff. of friction at the contacts b/w disc and surfaces is .3.

15 comments:

  1. AmitSeptember 27, 2010 at 7:30 PM

    This comment has been removed by the author.

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  2. somay jainSeptember 27, 2010 at 7:46 PM

    im getting 5kg..

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  3. AmitSeptember 27, 2010 at 7:49 PM

    This comment has been removed by the author.

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  4. somay jainSeptember 27, 2010 at 8:00 PM

    there is friction on the wall too..
    also, for taking different direction of friction by the wall, i am getting different answers..

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  5. AmitSeptember 27, 2010 at 8:01 PM

    This comment has been removed by the author.

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  6. AmitSeptember 27, 2010 at 8:06 PM

    4.61kg

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  7. Sambhav GuptaSeptember 27, 2010 at 8:36 PM

    70/11 kg

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  8. ankush sachdevaSeptember 27, 2010 at 8:45 PM

    7.46 kg

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  9. AnujSeptember 27, 2010 at 9:05 PM

    Consider friction from the vertical wall also.

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  10. AmitSeptember 27, 2010 at 9:15 PM

    confirm the equations
    mg+N+*R=Mg
    R=*N
    mg(6)=*R(2)+*N(2)

    *=coeff. of friction
    N=normal due to ground
    R=force by wall
    m=block
    M=disc

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  11. Sambhav GuptaSeptember 27, 2010 at 9:16 PM

    ok, 7.46

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  12. AmitSeptember 27, 2010 at 9:18 PM

    tell about the equations sambhav

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  13. Sambhav GuptaSeptember 27, 2010 at 9:35 PM

    T=m1g

    T + N1 + (mu)(N2) = m2g

    (mu)(N1)=N2

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  14. Sambhav GuptaSeptember 27, 2010 at 9:36 PM

    also, 6T=(mu)(N1+N2)(R)

    ReplyDelete
  15. AmitSeptember 28, 2010 at 12:43 PM

    I have also made the same eqns, might be a calculation mistake

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