Anuj Kalia: Radius of Curvature

Radius of Curvature

Do you know how we find the radius of curvature of a particle's path?

A force 1i`+2j`+3k` acts on a particle (mass=2) moving with a velocity -2i`+3j`-k`. What is the radius of curvature of the particle's path at this instant?

6 comments:

shivam gargshyaOctober 17, 2011 at 5:31 PM
sqrt14(8/11i +18/5 j-2/7k )
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AnujOctober 18, 2011 at 12:18 AM
hi sumantra..try not to post the solution so soon!
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shivam gargshyaOctober 18, 2011 at 6:46 AM
ok bhaiya,btw bhiya i am shivam not sumantra
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RachitOctober 19, 2011 at 8:40 PM
I am Getting
20i` + 5j` + 26/3 k`

is it right or wrong?
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AnujOctober 21, 2011 at 12:45 PM
radius of curvature is a scalar.
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Pulkit MendirattaOctober 21, 2011 at 8:52 PM
i am getting 28root(14)/root(13)
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