So you don't know how to find the Radius of curvature?

Lets try it again.

A particle is projected with a velocity 10m/s at an angle 37* with horizontal. Whats the radius of curvature at t=0? At what instant is the radius of curvature minimum?

Find the radius as a function of time.

5 comments:

  1. r(t)=[(6-gt)^2 +64]^(3/2)/8g
    at t=0,r=12.5m
    min at t=0.6s

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  2. getting same as above when used the angle b/w vectors approach.. but getting a messy and not same equation when took component of g perpendicular to v,and then found magnitude.

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  3. YAA me too gettin messy when took component of g perpendicular to v,and then found magnitude.

    how to do using this way ??

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