Angular Momentum


A particle is projected with speed 'v' at an angle 'Q' with the horizontal. Find its angular momentum about the point of projection after time 't'.

11 comments:

  1. mv cos(theta)gt^2/2 inside the plane

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  2. (1/2)mvgt^2cosQ inside the plane ?

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  3. same as above but does this result tells us something??

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  4. yes , i also want to know what is interesting in the result obtained .....

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  5. as far as I know, not much is interesting. However, there are 2 ways to find out the angular momentum. I wanted you to use the easier way!

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  6. by expressing r and v in vector form, makes this question in just three lines

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  7. yes no questions since long time ?????

    why ????????????

    plz post some ....

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  8. You can check out all the previous year questions for the meantime,till activity on blog resumes.
    The blog boasts of a collection of many goood problems,do check them out.

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  9. obviously, i've run out of problems. i never 'made' problems. all the questions on this blog were based on things that I had done during JEE prep.

    still, let me see if I can remember a few more..

    Pulkit is right btw...there are very many old problems on my blog! Try the ones from early 2010 (use the archive)!

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