Seven identical beads are sliding on a meter rod as shown. Their positions and velocities are listed. A positive velocity indicates motion to the right.
When a bead slides off the meter rod, a Dragon awakes. Presently, its t=0.
At what times does a Dragon awake? Note that a total of 7 Dragons will wake up. List all the 7 time instants.
Click the image to enlarge and notice the minus signs.
oh c'mon people!
ReplyDeletealright, the answer is: Dragons awake at:
ReplyDelete(1-.1)/.1, (1-.2)/.2, .4/.3, .6/.1, (1-.65)/.1, .8/.3, .9/.4
seconds
this much simple ... how ??
ReplyDeletecan u explain .....
we know that during a head-on elastic collision b/w 2 identical balls, their velocities are interchanged.
ReplyDeletenow if you think about it, it is as if the collisions b/w the beads never take place. it is as if the beads just 'go through' one another.
all this is after assuming that the beads are small.
what is the use of the fact that " the beads are small" in supporting that beads can be assumed to go through one another ?
ReplyDeletesomeone plz reply !!!
ReplyDeleteTry it for very large balls. For example: consider only 2 balls moving towards each other with speed 1m/s. Assume both have radius .2m and are initially located at x=.2 and x=.8.
ReplyDeleteThe answer will be different (and much easier to calculate) if the balls are tiny.
In the 1st case, both balls will fall off at t=.5 seconds.
In the second case, both fall off at t=.8 seconds.
Note: times= (1-.2)/1, (.8)/1.