Moment of Inertia:

Find the moment of inertia of a hollow cone of mass 'M', and base radius 'R'.

PS: I know I'm repeating this problem.

5 comments:

  1. AbhishekJuly 31, 2011 at 10:08 PM

    3/10 mr^2

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  2. MayankAugust 1, 2011 at 10:58 AM

    Moment of inertia of a right circular cone about an axis passing through its vertex and perpendicular to its base = 3/10MR^2

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  3. AnujAugust 1, 2011 at 12:29 PM

    hollow cone.

    ReplyDelete
  4. MayankAugust 2, 2011 at 1:11 PM

    sorry, didn't read that..1/2MR^2..?

    ReplyDelete
  5. AbhishekAugust 2, 2011 at 4:40 PM

    sorry, didn't read correctly , 1/2 mr^2

    ReplyDelete

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