Easy, yet Interesting!
Given are 2 positively charged infinite rods of a finite charge density k.
The rods, both move parallel to their length with a speed 'v' in the same direction. Find 'v', if they are to remain in equilibrium.
Bonus question:- A particle of charge q and instantaneous position r, is moving with a velocity v. Find the magnetic field vector at a point with position vector r1.
speed of light
ReplyDeleteyeah, speed of light... dont kno if its possible though, coz a lot of things cum into action ven u start talking about moving at light speed
ReplyDelete@bonus: mu*q[Vx(r1-r)]/4pie|r1-r|^3 ?
here x denotes cross product
can this be done with only electrostatics knowledge
ReplyDeleteas i am unable to solve this question
and please also post the solution os electostat question (two spheres wala)
no, electrostats is not enough for this
ReplyDeleteand the solution to that had been provided long time back, check the post itself
is my answer right?
ReplyDeleteyes 'anonymous 2', you are right
ReplyDeleteand very well done for the bonus question, I couldn't get it myself the first time I saw it.
Nice work guys..Sambhav you're mod now?good :).. n yes lot of shit happens near c so prac plausibilty in 'present' sciences is not possible( politically correct ;) )..keep up the good work
ReplyDelete