Don't Get this Wrong!


Two bobs, tied to each other by an ideal string, lie on a smooth, frictionless horizontal table.

A sudden impulse 'J' is imparted to the bob of mass 4m. Find (x+y), if the tension in the string just after the impulse is [x(J^2)]/[yml].

Use Judge-'Impulse'

6 comments:

  1. AnujJune 2, 2011 at 8:20 PM

    nice (and easy if done with some pseudo forces)..

    ReplyDelete
  2. ABHISHEKJune 2, 2011 at 9:04 PM

    This comment has been removed by the author.

    ReplyDelete
  3. AnujJune 2, 2011 at 10:16 PM

    the tension in the string just after the impulse is given is [x(J^2)]/[yml]

    ReplyDelete
  4. AnonymousJune 5, 2011 at 1:31 AM

    Disappointed..:(

    i'm getting 4+125= 129.....whats the right answer......nd how?

    ReplyDelete
  5. Sambhav GuptaJune 5, 2011 at 2:56 PM

    COM is 4l/5 meters from the mass m, use angular impulse-angular momentum equations to get angular velocity about COM, then use T=m(w^2)r, where r=4l/5


    alternatively, you can do the same for the mass 4m also
    answer is, x=1, and y=20

    ReplyDelete
  6. rishabhJune 6, 2011 at 9:45 PM

    this is the most easiest question

    ReplyDelete

Subscribe to: Post Comments (Atom)