Applying JEE knowledge:

6 comments:

  1. connecting a resistence in series...such that potential drop across the filter is 2 V....

    and remaining 3 across the external resistence..

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  2. This comment has been removed by a blog administrator.

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  3. though i loved the last comment, i can't allow it here.

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  4. as written above ....resistances in series will be the easiest option........(just a bit of electricity will be wasted though :P)

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  5. wats d final answer, bhaiya?

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  6. the answer was:

    1)run to electrical engg (EEL101) lab and pick 5 resistances that look similar (color-coding).

    2)run back to h/w lab, connect them in series across the 0->5 volts, and tap out the required voltage from the 2nd resistance.

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