The simpler, the merrier.

I' scrapping this question...you would never solve it as it seemingly can't be solved...i tried some graph plotting software but could make nothing...some people more skilled in trigo. would have done it maybe...

And, as you can see, i'm really out of cool problems. I'll try to make some oer the weekend.
See you on monday.

7 comments:

  1. ankush sachdevaApril 10, 2010 at 2:17 AM

    sin inv 1/45 with the horizontal
    assuming w to be constant (which i obviously know is a wrong assumption)

    i need a bit of help...just tell me
    how to find the angular momentum of sleeve if its at a distace x frm hing??

    ReplyDelete
  2. guntashApril 10, 2010 at 9:29 AM

    sin inv 0.87.........

    ReplyDelete
  3. AnujApril 10, 2010 at 10:34 AM

    hi sambhav. you must find the perpendicular distance of the sleeve from the axis...and component of velocity perpendicular to this.

    thats the ans. to YOUR question, not mine..

    ReplyDelete
  4. ♥◘○µ╦┬░Γ╪╬└↑φΦ╫╛◙«½╣↔⌐☺♠♦♣◘○April 10, 2010 at 1:39 PM

    This comment has been removed by the author.

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  5. ♥◘○µ╦┬░Γ╪╬└↑φΦ╫╛◙«½╣↔⌐☺♠♦♣◘○April 10, 2010 at 1:39 PM

    This comment has been removed by the author.

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  6. ♥◘○µ╦┬░Γ╪╬└↑φΦ╫╛◙«½╣↔⌐☺♠♦♣◘○April 10, 2010 at 4:52 PM

    This comment has been removed by the author.

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  7. ♥◘○µ╦┬░Γ╪╬└↑φΦ╫╛◙«½╣↔⌐☺♠♦♣◘○April 13, 2010 at 8:01 PM

    today is TUESDAY..........

    ReplyDelete

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