Plz. note:



In the first diagram, note that though v1CosA=v2, same constraint does not hold for accn.

In the second diagram, v1(1-CosA)+v2=0 but not a1(1-CosA)+a2=0...




I wanted you to observe that you can relate the velocities by taking the tensions..



Try it: in each question, observe the tension (in the dirn. of motion) and the coefficients in the velocity constraints...

12 comments:

  1. ♥◘○µ╦┬░Γ╪╬└↑φΦ╫╛◙«½╣↔⌐☺♠♦♣◘○April 6, 2010 at 8:40 PM

    SEE MY COMMENTS IN THE PREVIOUS PROBLEM SIR

    ReplyDelete
  2. Sambhav GuptaApril 6, 2010 at 8:44 PM

    well that was nice...:)
    thnx especially for this one!!

    ReplyDelete
  3. AnujApril 6, 2010 at 9:00 PM

    yes, i saw the diagram..i can't make anything from it..you have not shown overlapping of the loops ie. how the wire is structured..
    without that how can one find the B??

    and, you can consult your teachers regarding these..
    i operate this blog so you can have something that you won't have in class..

    you can see that each question here can be generalized to several more...while the problem you uploaded is a specific case of finding the magnetic field...

    i can't really help you there...sorry for being harsh yaar...but that's the way things are.

    ReplyDelete
  4. ♥◘○µ╦┬░Γ╪╬└↑φΦ╫╛◙«½╣↔⌐☺♠♦♣◘○April 6, 2010 at 9:03 PM

    OK SIR,I ONLY LISTEN TO YOUR PROBLEMS IN THIS BLOG

    ReplyDelete
  5. ♥◘○µ╦┬░Γ╪╬└↑φΦ╫╛◙«½╣↔⌐☺♠♦♣◘○April 6, 2010 at 9:05 PM

    I USE Re = 6.378x10^6 m and g = 9.81 m/s^2

    ReplyDelete
  6. AnujApril 6, 2010 at 9:09 PM

    cool yaar...i'll verify your answer soon

    ReplyDelete
  7. ♥◘○µ╦┬░Γ╪╬└↑φΦ╫╛◙«½╣↔⌐☺♠♦♣◘○April 7, 2010 at 1:06 PM

    PLEASE REPLY SIR,SO THAT IF MY ANSWER IS WRONG I RETRY IT..........

    ReplyDelete
  8. AnujApril 7, 2010 at 1:26 PM

    amritpal, what was the value of the acceleration that you took???

    it would be easier for me to verify...

    ReplyDelete
  9. ♥◘○µ╦┬░Γ╪╬└↑φΦ╫╛◙«½╣↔⌐☺♠♦♣◘○April 7, 2010 at 1:30 PM

    This comment has been removed by the author.

    ReplyDelete
  10. ♥◘○µ╦┬░Γ╪╬└↑φΦ╫╛◙«½╣↔⌐☺♠♦♣◘○April 7, 2010 at 1:42 PM

    This comment has been removed by the author.

    ReplyDelete
  11. AnujApril 7, 2010 at 8:37 PM

    then your answer is probably right...

    ReplyDelete
  12. ♥◘○µ╦┬░Γ╪╬└↑φΦ╫╛◙«½╣↔⌐☺♠♦♣◘○April 7, 2010 at 8:57 PM

    i remove my post for secrecy...

    ReplyDelete

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