
Somebody made a giant spherical cavity in the earth such that the earth's center and a point in the surface are diametrically opposite.
The someone drops a small ball from a small opening at the surface into the cavity. In how many minutes does the ball reach the center of earth???
acc ke do expression to aa gaye but integrate nahi ho pa raha
ReplyDeleteThis comment has been removed by the author.
ReplyDeleteis the answer is 26.87 minutes.
ReplyDeleteThis comment has been removed by the author.
ReplyDeletePLEASE VISIT IN THE FOLLOWING LINK TO SEE MY DOUBT http://www.goiit.com/posts/list/magnetism-please-solve-this-mutimatching-problem-1014340.htm
ReplyDeletei have only one conceptual doubt.It is a multimatching problem.only tell in column 2 option (s) matches with what options in column 1 and why?please give detail reasoning please.dont give shortcut reasoning please sir HELP ME!!!!
ReplyDeleteyr tune yeh link daalkar iss question ka saara essence khatam kar dia...
ReplyDeleteI CANT MAKE DIAGRAM IN THIS BLOG.SO SAMBHAV DONT FEEL BAD ABOUT ME PLEASE.I HAVE NO OTHER OPTION
ReplyDeleteI USE Re = 6.378x10^6 m and g = 9.81 m/s^2
ReplyDeletesomeone else with a soln????
ReplyDeleteanybody with any idea of the nature of field in the cavity??
field in a hollow sphere is uniform..?
ReplyDeletedunno anything about this....gravitational was left out...they told us that it would be covered in electrostatics
damn...
ReplyDeleteuse the formula for acc (GM/R^2)*x/R for the 2 spheres and subt. then integrate and t1,t2
ReplyDeletewould the ball be ever able to reach the center of earth 'on its own' ?
ReplyDeletemaybe you people will get to know this later...
ReplyDeletebut the field in a cavity in a uniform sphere is same as that at the centre of the cavity had there been no cavity.
here, the field is that at R/2 when there was no cavity..which is equal to g/2...(remember that graph of g v/s r..its linear remember...)
and sambhav..i guess it will...this ain't my question, so most probably its correct.
BHAIYA
ReplyDeletePLEASE TELL HOW TO SOLVE THIS QUESTION