Hourglass




A "water"-hourglass is to be constructed such that the scale is uniform.
That is, the ratio of height difference between the level of water at two time instants to the time difference is a constant.


Your task is to find the mathematical equation the glass follows.. ie, report d log z / d log r accurate upto 3 decimal places at the judge.
Assume the hole to be infinitessimally small.
Also assume negligibe change in air pressure.

13 comments:

  1. MayankAugust 28, 2011 at 3:06 PM

    Great application(though easy, mathematically) of quite a basic result!

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  2. MayankAugust 28, 2011 at 5:28 PM

    Bhaiya please post the solution to the 'Surface tension' question, in case it's not what everyone has posted.

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  3. ShivankerAugust 30, 2011 at 9:30 PM

    comments invited..

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  4. RohinAugust 30, 2011 at 10:00 PM

    please give a hint? first of all,maths ka question hai ya physics? :P (maths i guess)
    what to do after dz/dt=const. ?

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  5. AbhishekAugust 30, 2011 at 10:34 PM

    is the equation of glass y=k(x^4).....

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  6. AbhishekAugust 30, 2011 at 10:37 PM

    WHAT IS THE FINAL ANSWER TO THE MECHANICS QUESTION?????????????????????????????????????????????????????????????????????????????????????

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  7. rishabhAugust 31, 2011 at 3:50 PM

    to rohin:
    this question is of physics and maths
    a hint- use equation of continuity and
    rest is simple maths

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  8. AbhishekSeptember 1, 2011 at 7:09 PM

    IS MY ANSWER RIGHT ?? PLZ CONFIRM..

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  9. ShivankerSeptember 1, 2011 at 10:14 PM

    yes u're right abhishek..

    and yes rishab is right rohin..
    I would even say that whole of Maths is "dense" in Physics.!

    P.S.: Wiki "dense set"
    :D

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  10. RohinSeptember 2, 2011 at 1:02 AM

    ^ jst saw on wiki.i myself feel maths is the language of phy.and dense set is the closest way to describe it :D
    i was thinking it is purely maths based.anyway,got the answer now.

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  11. rishabhSeptember 2, 2011 at 5:06 PM

    please give the explaination to
    "Simple Mechanics" question

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  12. NaveenSeptember 3, 2011 at 7:06 PM

    Please give the detailed solution.I am confused !

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  13. AnujSeptember 4, 2011 at 10:37 AM

    hi rishabh.

    you can leave that particular problem for now. its not making much sense to me either!

    ReplyDelete

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