JEE 2011:



Here's one concept that was highlighted in the paper. Literally, people (including me) fought over the validity of the problem. (Q 33, Paper 1).

Lets not get into the problem. Instead, lets do something simpler.

The vertical black rod is mass-less. The blue rod has mass 'm'. The vertical rod is rotated at an angular velocity 'w'. Calculate the kinetic energy of the system for two cases:

1)Blue rod is free to rotate about 'A'. ('A' is then called a 'hinge' joint).
2)Blue rod is not allowed to rotate about point 'A'.

P.S. Hope the blog readers did well!

14 comments:

  1. Acc. to me..
    K(a)= 1/2 m.w^2.L^2
    K(b)= 1/2 m.w^2.L^2 + 1/2(m.a^2/12)w^2

    but i messed up the question in the exam!

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  2. even the solution wasn't clear to me.. but after seeing this question.. i think i got it.
    Thanx bhaiya!
    Hope m correct here...

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  3. 1)We'll not discuss ppl's marks here.

    2)Your answer is right. But the important thing is to visualize the motion of the blue rod.

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  4. ppr k time bhi galat kia tha, and abhi bhi samajh nhi aaya

    why is omega of com of rod about hinging point same as omega of rod about com?

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  5. bhaiya, please explain the motion of the rod. Couldn't get it!

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  6. sambhav, just try to visualise, jab rod move hi nhi kari abt hinge, toh w[rod]=w, taking wall ka hinge as centre

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  7. hey, please clear.
    according to my visualisation, the answer shivanker gave to (a) should be for (b) and vice-versa.
    I mean in (b) part, it isnt allowed to rotate.
    please clear this

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  8. ok i got the motion now, good question by jee!

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  9. Hi Pulkit,
    Shivanker's answer is right. Try once again.

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  10. hey please explain the motion to me also.thanx

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  11. And first of all make me clear motion is like a pendulum or what?

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  12. have 11th class students (now 12th) done summation of series?

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  13. yes they must have, this is the time we did conics/calculus

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