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We plan to keep the block of mass 'm' stationary wrt. the wedge by accelerating the latter to the left.

This is possible for a significantly wide range of accelerations. Infact, the acceleration can be anywhere between g*tan(A) and g*tan(B). However, a certain value of acceleration, equal to g*tan(C) is of significant interest.

Your task is to report the values of A,B,C; in degrees. Your answer should be 3 comma separated values, correct upto 2 places of decimal.

Note:
Angle of the incline: 60*.
Coeff. of friction b/w wedge and mass: 1.
PS. : we've done a very similar problem before.

19 comments:

  1. this is 'troll mathematics'? tan 105 is -ve!

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  2. i had a doubt about it earlier too
    dunno, still feel 15, 60, and 105 correct for the present scenario

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  3. an -ve accn? would like to hear the reasons behind that...

    lets keep the accn. positive here..give a range in the positive values.

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  4. the answer must be 0, 60, 75 but don't know why isn't it accepting..

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  5. At '0', accn. is 0.

    With '0' accn., the block would slip down.

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  6. 1)someone tell me about this 75*?? how are u getting this.
    here's a hint (which solves the problem completely): does the block slip at infinite accn.?

    2)@amit: your answer is probably wrong. the 'judge' (thats what we call an automated answer checker) is probably right.

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  7. Bhaiya, the block does slip at infinite acceleration
    me getting the same answer as amit

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  8. This comment has been removed by the author.

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  9. m sorry.. m getting 15, 60 and 90.. finally! but the judge still says its incorrect..

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  10. Yes block does slip at infinite acceleration.

    PS- I would say jiska bhi answer galat hai na(including me excluding bhaiya) use chullu bhar paani mein doob kar mar jaana chahiya. IIT 'SIRF' isi saal dena hai :D

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  11. @shivanker, please xplain how you got 90, At infinite acc wont block move up???

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  12. let mu=tanR=1, hence R-45

    now, why is the answer not gtan(60-45), gtan(60), gtan(60+45)

    just like we do in case of car on a banked curve, vahan bhi to acceleration is horizontal, isn't it a perfect analogy?

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  13. or, this means(i think i shud have said it before only) that there no upper limit for acc for which block remains stationary wrt wedge

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  14. ok got my mistake. no need of chullu bhar paani- question acha tha.

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  15. so whats the final answer?

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