
The diagram shown is that of a "FLYBALL GOVERNOR". It consists of 2 bearings 'A' and 'B'. 'A' is fixed while 'B' can slide up and down the rod.
The bearings are attached to 2 massive balls (assume 1000kg balls). The balls are spinning with a speed 10m/s.
The speed of the balls can be 'governed' by adjusting the distance between the bearings.
The distance is reduced (slowly and smoothly) form 1m to 1/2m.
What is the new speed of the balls?
NOTE: ignore the '3m' shown in diagram.
i am back bhaiya
ReplyDeleteI am getting 22.5 m/s
ReplyDeleteplease tell bhaiya is my answer 22.5 m/s correct??
ReplyDeleteoops sorry bhaiya,your figure is not correct.Please see the figure dimensions.
ReplyDeletebhaiya please change the values of the length of the rod bcoz 1+1<3 therefore, triangle is not possible.
ReplyDeleteisnt there some problem bhaiya??
ReplyDeletethe right triangle made by either bearing, either ball and the rod, seems to have a longer perpendicular than the hypotenuse..
BHAIYA please make that earlier system of comments only. isme maza nahin aa raha. Also, if you have done this bcoz some directly post the answer and other agree then, the latter are only a the losing end.You can take the view of others also. Also, I think here dimensions are wrong.
ReplyDeletesqrt(90)?
ReplyDeleteSorry guys. A few days back, i turned comment moderation on, for no good reason. and then i forgot all about it.
ReplyDeleteLater, the page was showing 'o comments', so I thought that no one had solved it!!
So: I have corrected the problem. My mistake. Please ignore the '3m' shown in diagram.
4sqrt(5)
ReplyDeletejust a wild guess
ReplyDelete10sqrt(6/7)
4sqrt(5) should be the answer. Apply conservation of angular momentum about axis A-B.
ReplyDelete@sambhav, how itna ganda answer and that too wild guess. we just have to conserve the angular momentum of the system.
ReplyDeleteoh didn't see bhaiya has replied
ReplyDeleteyr kia to maine bhi angular momentum conserve tha, par orally kia tha, pata nhi kaise aaya
ReplyDeletev1r1=v2r2
r1 aur r2 kya lia?