AML110 major:


You could have probably solved at least two problems from our AML110 major exam.

Here's the first:
A rod is constrained to move b/w two fixed cylinders. The cylinders however are free to rotate about their natural axes.

Find the acceleration of the rod.

Radius of the larger cylinder = .6m.
Radius of the smaller cylinder= .3m.

8 comments:

  1. AmitNovember 22, 2010 at 2:07 PM

    I am getting 100/23

    ReplyDelete
  2. shaanNovember 22, 2010 at 3:47 PM

    yup.. 100/23.

    ReplyDelete
  3. Pratik JainNovember 22, 2010 at 4:54 PM

    yes 100/23 assuming no relative motion at the points of contact..

    ReplyDelete
  4. AmitNovember 22, 2010 at 7:35 PM

    http://www.imaginationcubed.com/loader.php?aDrawingID=1e4674b293773275827cb08d28355187&from_email=amit.mittal1993%40gmail.com&from_name=amit

    bhaiya or anyone please help me out in this question. Answer is F/4(m+C{BL}^2)

    thanx

    ReplyDelete
  5. Sambhav GuptaNovember 22, 2010 at 8:28 PM

    This comment has been removed by the author.

    ReplyDelete
  6. Sambhav GuptaNovember 22, 2010 at 9:16 PM

    amit, 5 equations in 5 variables
    1)BvL=R(I1)
    2)BaL=(I2)/C
    3)I1+I2=I
    4)F-BIL=ma
    5)F=(BL)^2(v-terminal)/R

    ReplyDelete
  7. AmitNovember 22, 2010 at 9:33 PM

    oh thanx sambhav, I got my mistake.

    ReplyDelete
  8. shaanDecember 8, 2010 at 3:47 AM

    sambhav,please confirm
    you missed out

    MG in 4)

    and in 5) it shud b 3/4 v-terminal

    ReplyDelete

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