IIT D CYL110 quiz 1


Consider this: this problem appeared in our CYL110 (a 2nd semester chemistry course) quiz...half the CS department couldn't get it right!

This gas undergoes a reversible process s depicted in the P-V curve...the center of the circle shown is (10,10) and its radius is 5;

You know whats coming...find the maximum temperature of the gas!

14 comments:

  1. This comment has been removed by the author.

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  2. oh god...too much algebra involved!!!

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  3. srry....made a blunder...is it at (10+(5/root2), 10+5/root2))

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  6. vaibhav, your approach was nearly the same as what i applied...though you could have used some other curve instead of the 'line'..

    what could be this 'some other curve'???

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  7. anuj bhaiya ,can u please give ur approach

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  8. yeah got same ans as vaibhav,
    solved it like a trigo question,realised something obvious on seeing the ans

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  9. oh shit...was playing with algebra
    parametric equation proved much, much easier..!!

    yea the answer was obvious already

    getting nRT as 100 + 12.5 + (50sqrt[2])

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  10. Bhaiya...i cud not get d curve u were talking about...

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  11. hi Vaibhav...you approach was cool, but i used the hyperbola PV=const...kind of the obvious curve for the isotherm...

    as the distance of the hyperbola increases, temperature increases...then the answer follows from Symmetry!...

    and asking for the maxm. temp was in a way incorrect...should have specified the no. of moles...

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  12. hm..

    eqn is of a circle (x-10)^2 + (y-10)^2 = 25

    for max temp
    xy shud be max which at x = y (by am>gm)
    ans is at P=V=10+(5/root2)

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  13. hi ankush...cool use of THE inequality!!

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  14. Simple AM>GM was enough.. it would be when P=V and both are max so this gives 10+5/root2 P and same V.
    same approach as ankush

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