Many people cleared the JEE today..congrats to em all! Further, the blog now boasts of 60 followers..so congrats to me.
Now, this question HAS a history with me..
Particle 'A' is located at (1,2,3), and particle 'B' at (-1,-2,6). A has a constant velocity V1(vector), B has V2(vector).
Find the unit vector in direction of (V2-V1), if A and B are supposed to collide somewhere in the future.
i've gotten used to seeing this "0 comments"...cmon people..we need an answer here!
ReplyDeletewont there be infinite answers to this
ReplyDeletethey can collide head on or obliquely
since there are no restrictions on V1 and V2
hey anuj,
ReplyDeletecould u tell me how the online JEE counselling works ( since u would have filled ur options last year )
I want to know if we have to provide our preferences for only courses or branches or both
( or in case anything else )
(2i+4j-3k)/root29 ?
ReplyDeleteankush, you're wrong...akash is right.
ReplyDeletehi kapil...i don't really much abt. the online counselling..we had ours in iit delhi.
someone got to tell me how...
ReplyDeletei feel this is the easiest ques on blog till now
ReplyDeletejust draw 2 points on coordinate plane, then draw their velocity vectors
CATCH THE HINT IN QUES-they collide after sometime
this becomes ques of simple vector addiction
will leave the rest to you :)
ya this one was easy...
ReplyDeleteV1 and (-V2) form the two sides of the triangle whose third side is the vector joining the two given points....this vector also represents the required vector sum...
Thnx yr akash!
Mr.Rupela is right..but i wanted u to revisit the eqn. of uniform motion in vector form:
ReplyDelete_ _ _
r(t)=r1+v1*t
_ _ _
R(t)=r2+v2*t...
,
for them to collide: R(t)=r(t) for some t=t...
rest follows..
good ques....chalo module 3 bhi revise kara diya(almost)
ReplyDeleteare we supposed to know abt the 'history'..?
ReplyDeletesorry guys...just not getting enough time to put up something good. Sambhav knows why 3:)
ReplyDeleteARRe put some q. re
ReplyDelete