Google Rude

Today I was trying a website which generated rude comments everytime it was refreshed. Some of the rude comments were:
"Ya silly ninny!"
"Ya mouth breather!"
"Ya COBOL expert!"

Looking closely, I realized that the website chose a random comment whenever it was refreshed. It chose the comment randomly from a set of 100 rude comments.

After a while, I started seeing comments I had seen before, and the website became boring for me.
Can you tell me the probability that I have already seen the comment that I see on my 10th refresh?

8 comments:

  1. AbhishekMay 17, 2012 at 7:23 AM

    This comment has been removed by the author.

    ReplyDelete
  2. AbhishekMay 17, 2012 at 11:57 AM

    IGNORE PREVIOUS COMMENT !!

    Now the answer is ::

    { 100C9 / 100C9 } *{ 9C1/91C1 } + { 100C8/ 100C9 } * { 8C1/92C1 }+ {100C7/100C9 }* {7C1/93C1 }+......+ { 100C1 / 100C9 } *{ 1C1/99C1 }

    ReplyDelete
  3. AbhishekMay 17, 2012 at 11:58 AM

    IGNORE PREVIOUS COMMENT !!

    Now the answer is ::

    { 100C9 / 100C9 } *{ 9C1/91C1 } + { 100C8/ 100C9 } * { 8C1/92C1 }+ {100C7/100C9 }* {7C1/93C1 }+......+ { 100C1 / 100C9 } *{ 1C1/99C1 }

    ReplyDelete
  4. AnujMay 22, 2012 at 6:18 PM

    No correct answer yet? I think its pretty simple.

    ReplyDelete
  5. AnujMay 25, 2012 at 12:37 PM

    Here's a hint:

    Lets consider the 10th comment, and assume that its the kth comment, k can be anything b/w 1 and 100. The probability of this happening is 1/100.
    What is the probability that this is a new comment?

    ReplyDelete
  6. shivam gargshyaMay 28, 2012 at 5:39 PM

    if in the list ,at the 10th place a song is repeated first time,then the answer is 100c9*9!*9c1.
    but if the songs can repeat themself before 10th place
    well in that case mujhse nahin hua :P
    i tried it but many cases were getting formed (like if songs are repeated twice or songs are repeated thrice in that case too if same song repeated it self or different songs repeated themself so acchi khasi series ban rahi thi so i left it.

    ReplyDelete
  7. AnujMay 28, 2012 at 6:43 PM

    Lets consider 3 songs {A,B,C} and the the 3rd turn.

    Total possibilities: 27
    Favorable cases:

    1)3rd song is 'A' {BBA, BCA, CBA, CCA}
    2)3rd song is 'B' {AAB, ACB, CAB, CCB}
    3)3rd song is 'C' {AAC, ABC, BAC, BBC}

    Is there something that I'm doing wrong? I don't think so.

    ReplyDelete
  8. shivam gargshyaMay 29, 2012 at 10:38 PM

    ignore the prev. comment i was solving a easy question stupidly the answer is
    1 - 100c10*10!/100^10

    ReplyDelete

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