Some Thermochemistry

Find ΔS and ΔG for the conversion of 10.0g of supercooled water at -10° C and 1 atm to ice at -10° C and 1 atm. Average cp values for ice and supercooled water in the range 0° C and -10° C are 0.50 and 1.01 cal/(°C g) respectively. Given that the latent heat of fusion of ice is 79.7 cal/g at the normal boiling point.

6 comments:

  1. ΔS= -74.6 cal/° C and ΔG is equal to zero?

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  2. i did it like this !!

    ΔS total = ΔS(water[-10°C] to water[0°C]) + ΔS(water[0°C ]to ice[0°C]) + ΔS(ice [0°C ]to ice [-10°C]).....

    ΔS total = 10*(1.01)*ln (273/253) + (79.7 * 10) /273 + 10* 0.5 * ln(253/273)


    plz verify !!


    or spot the mistake !!

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  3. @Abhishek:

    1. its 263, not 253
    2. the second term should be negative as heat was released.. :)

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