More on the center of rotation method:


Well, this sounds like I'm making it up, but the day I noticed the method, I was up all night trying to find out "cases" where the method won't work.

Consider the diagram (i). Try calculating the angular acc. of the main pulley using 2 methods: C.O.R. method, and the usual (and correct method). You will notice that C.O.R. method gives a wrong answer.

So, I concluded: apply C.O.R. method only for problems with single rigid bodies, with a center of rotation.

Now that you know the C.O.R. method, can you solve:this question that was specially designed to illustrate the C.O.R. method?

3 comments:

  1. AnujDecember 5, 2011 at 3:40 PM

    with some thought and proctice, the C.O.R. method can be applied to question (ii)

    ReplyDelete
  2. ShubhamDecember 7, 2011 at 8:20 PM

    Will whole of m1 and m2 be considered to be present on the top most point (where the plank touches the spheres) individually for each sphere?...i.e. would the denominator in the expression of ang acc of any one of the sphere be= Mk^2+MR^2+m1(2R)^2+m2(2R)^2

    ReplyDelete
  3. AnujDecember 8, 2011 at 12:45 AM

    the best way is to solve using the standard method and see what's happening.

    ReplyDelete

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